Given: T1 = 27 °C = 27 + 273 = 300 K,
v1 = 340 m/s,
T2 = 127 °C = 127 + 273 = 400 K
To find: Velocity (v2)
Formula: \(\frac{v_1}{v_2}=\sqrt{\frac{T_1}{T_2}}\)
Calculation: From formula,
v2 = v1 \(\sqrt{\frac{T_2}{T_1}}\) = 340, \(\sqrt{\frac{400}{300}}\)
= 340 × 1.1547
∴ v2 = 392.6 m/s