1. nadius of Boho's \( 4^{\text {th }} \) onbit fon t 1 atom
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The number of elliptical orbits present in Bohr’s third orbit
Correct option is B) 2
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When an electron jumps from higher orbit to lower orbit in an atom the energy is …………….
Correct option is B) emitted
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Explain briefly the results of Bohr’s theory for hydrogen atom.
i. The stationary states for electrons are numbered n = 1, 2, 3……. These integers are known as principal quantum numbers. ii. The radii of the stationary states are rn =...
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What is the wavelength of the photon emitted during the transition from the orbit of n = 5 to that of n = 2 in hydrogen atom?
Given : ni = 5, nf = 2 To find : Wavelength of the photon emitted Formulae : i. \(\bar v\) = 109677 [\(\frac{1}{n_f^2}\) - \(\frac{1}{n_i^2}\)] cm-1 ii. λ = \(\frac{1}{\bar v}\) Calculation : According to Rydberg equation [formula (i)], \(\bar v\) = 109677 [\(\frac{1}{n_f^2}\) -...
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The energy required to remove an electron from the outermost orbit or shell of a neutral gaseous atom is
B) ionization energy
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The energy of electron in the nth Bohr orbit of H-atom is …………
Option : (C) \(-\frac{2.18\times 10^{-18}}{n^2}J\)
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21. The ratio between kinetic energy and the total energy of the electrons of hydrogen atom according to Bohr's model is (a) \( 2: 1 \) [Pb. PMT 2002] (c) \( 1:-1 \) (b) \( 1: 1 \) (d) \( 1: 2 \)
Kuch bhi
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1. Radius of Bohr's forth orbit for hidrogen atom
We Know that, r = 0.529 x \(\frac{n^2}{z}\)pm Where, n = Orbit Number (Principle Quantum Number) z = Atomic Number ∴ r = 0.529 x \(\frac{4^2}{1}\) = 0.529 x 4 x 4 = 8.464 pm
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The number of electrons present in outer most orbit of an atom is called ……………… electrons.
Correct option is A) valency
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