Calculate the amount of heat required to convert 5 gm of ice at 0° C to water at 100° C. 

Mass (m) = 2 kg = 2 × 103 g. latent heat of fusion for ice (L) = 80 cal/g. To find: Heat energy (Q) Formula: Q = mL From formula, Q = 2 × 103 ×...

C) latent heat of fusion

Correct option is  B) 80 cal

Correct option is  A) Q = mL

Correct option is  B) 1 g

Correct option is  B) 2,700 cal

Correct option is  A) 3, 500 cal

Correct option is  B) 250 cal

Correct option is: (B) 1.02 kcal

(A) 136 km When the piece of ice falls from the height h, it possesses potential energy, mgh. This P.E. is converted to heat energy. ∴ Q = mgh But only \(\frac{1^{th}}{4}\) of it is absorbed...