The percentage of oxygen in NaOH is ……………
(A) 40%
(B) 60%
(C) 8%
(D) 10%
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Complete and balance the following chemical equations. (i)`BrO_(3)^(-)+F_(2)+H_(2)Oto` (ii)`F_(2)+NaOH ("dilute & conc.) to` (iii)`NaOH (aq) ("hot and
Correct Answer - (i)`F_(2)+ BrO_(3)^(-) + H_(2)Oto2F^(-) + BrO_(4)^(-) + 2H^(+)` (ii)`2F_(2)+2NaOH("dilute")toOF_(2) (g) + 2 NaF + H_(2)O` `2F_(2)+4NaOH("conc.")toO_(2) (g) + 4 NaF + 2H_(2)O` (iii)`2NaOH+undeset("cold & dilute")(Cl_(2))toNaCl + NaCIO...
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Although chlorine and oxygen have nearly same electronegativity yet only oxygen from hydrogen bond explain it ?
Correct Answer - Oxygen has smaller size than size, it cannot act as central atom in higher oxidation state.
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Which of the following is CORRECT? (A) 1 mole of oxygen atoms contains 6.0221367 × 10^(23) atoms of oxygen.
(D) All of these 1 mole of atom or ions or molecule or particle contains \(6.0221367 × 10^{23}\) atoms, or ions or molecules or particles respectively. Hence, option (D) is right answer.
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(i) Chalk contains calcium, carbon and oxygen in the ratio 10:3:12. Find the percentage of carbon in chalk. (ii) If in a stick of chalk, carbon is 3g,
Correct Answer - (i) 12% (ii) 25g
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The percentage of oxygen in inhaled air is
The percentage of oxygen in inhaled air is 21%
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The ratio of molecular weight of hydrogen and oxygen in water is 1 : 8. (The relation between hydrogen and oxygen in linear
Correct option is (A) y = 8x \(\because\) Quantities of hydrogen and oxygen are x and y and their quantity are in ratio 1 : 8. \(\therefore\) x : y = 1 : 8 \(\Rightarrow\) \(\frac xy=\frac18\) \(\Rightarrow\) y =...
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The ratio of molecular weight of hydrogen and oxygen in water is 1 : 8. (The relation between hydrogen and oxygen in linear
2 Answers
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Percentage of oxygen in air by volume ………………
Correct option is A) 20.9%
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The oxidation number of oxygen is …………. in oxygen difluoride.
Correct option is: (C) +2 The oxidation number of oxygen is +2 in oxygen difluoride because fluorine is more electronegative than oxygen.
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The oxidation number of oxygen is …………. in oxygen difluoride.
2 Answers
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