Explain with the help of a chemical reaction how limiting reagent works.

Monjur Alahi

Explain with the help of a chemical reaction how limiting reagent works.


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Salim Ahmed Kawsar

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  • Consider the formation of nitrogen dioxide (NO ) from nitric oxide (NO2) and oxygen. 2NO(g) + O2(g)  → 2NO2(g)
  • Suppose initially, we take 8 moles of NO and 7 moles of O2.
  • To determine the limiting reagent, calculate the number of moles NO2 produced from the given initial quantities of NO and O2. The limiting reagent will yield the smaller amount of the product.
  • Starting with 8 moles of NO, the number of NO2 produced is, 8 mol NO × \(\frac{2\,molNO_2}{2\,molNO}\) = 8 mol NO2
  • Starting with 7 moles of O2, the number of moles NO2 produced is, 7 mol O2 × \(\frac{2\,molNO_2}{1\,molNO}\) = 14 mol NO2
  • Since, 8 moles NO result in a smaller amount of NO2, NO is the limiting reagent, and O2 is the excess reagent, before reaction has started.

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