Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 goranges and 4 kg 150 g bananas. Who bought more fruits?
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Due to a rise of `12%` in the price of mangoes a dealer gets 27 kg less for Rs. 24750. Find (a) The new price per kg of mangoes. (b) The orginal price
Correct Answer - Rs. 110; Rs. 98
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A- water transport is used for international trade of bananas R-Bananas are perishable goods
ANSWER: (a) If both assertion and the reason are true and the reason is correct explanation of assertion. hope it help's you
2 Answers 6 views
Directions for questions 41 and 42 : A reduction of 20% in the price of mangoes per dozen enables a purchaser to bu 5 dozens more for ₹ 1800. Find the
Correct Answer - ₹72
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A person of mass 40 kg picked up a bag of mangoes and climbed ten steps . If the bag contains ten mangoes , each of mass `0.5` kg and the height of ea
Correct Answer - 450 J
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You are purchasing fruits from a street vendor. In what six ways you have to remain careful so that he does not cheat you while weighing the fruits?
Six ways to remain careful so that fruit vendor does not cheat while weighing the fruits- 1. Hollow bottom iron weights should not be used 2. Check magnet should not be there...
2 Answers 1 views
While eating fruits like pear or guava, it feels gritty. What gives stiffness to these fruits?
Sclereids are found in pulp of fruits like pear and guava which gives them stiffness and thus we feel gritty while eating these fruits.
2 Answers 1 views
What are aggregate fruits? Enlist the types of aggregate fruits.
The fruit which develops from a single flower with many ovaries of polycarpellary, apocarpous gynoecium is known as aggregate fruit or etaerio. Types of aggregate fruits: Etario of achenes (e.g. Strawberry), etario...
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Sneha went to market to buy the seedless fruits. Her daughter astonished how seedless fruits generate.
(B) Parthenogenesis
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Kishore bought 5 (3/4) kg apples and 4(1/2) kg oranges then find the total weight in kgs.
Correct option is (B) \(10\frac{1}{4}\) kg Total weight = \(5\frac{3}{4}\) + \(4\frac{1}{2}\) \(=\frac{5\times4+3}4+\frac{4\times2+1}2\) \(=\frac{23}4+\frac92\) \(=\frac{23+9\times2}4=\frac{23+18}4\) \(=\frac{41}4=\frac{40+1}4\) \(=10+\frac{1}{4}\) = \(10\frac{1}{4}\) kg.
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