Calculate the number of atoms in each of the following.
i. 52 moles of Argon (Ar)
ii. 52 u of Helium (He)
iii. 52 g of Helium (He)
i. 52 moles of Argon
1 mole Argon atoms = 6.022 × 1023 atoms of Ar
∴ Number of atoms = 52 mol × 6.022 × 1023 atoms/mol
= 313.144 × 1023 atoms of Argon
ii. 52 g of He
Molar mass of He = mass of 1 atom of He = 4.0 u
4.0 u = 1 He
∴ 52 u = x
∴ x = 52 u × \(\frac{1\,atom\,of\,He}{4.0u}\)
= 13 atoms of He
iii. 52 g of He
Molar mass of He = 4.0 g mol-1
Number of moles = \(\frac{Mass\,of\,a\,substance}{Molar\,mass\,of\,a\,substance}\)
= \(\frac{52g}{4.0g\,mol^{-1}}\)
= 13 mol
Number of atoms of He = Number of moles × Avogadro’s constant
= 13 mol × 6.022 × 1023 atoms/mol
= 78.286 × 1023 atoms of He
∴ i. Number of argon atoms in 52 moles = 313.144 × 1023 atoms of Argon
ii. Number of helium atoms in 52 u = 13 atoms of He
iii. Number of helium atoms in 52 g = 78.286 × 1023 atoms of He