A lawn is in the form of a rectangle whose sides are in the ratio 5:3 the area of the lawn is 3375 `m^(2)` .Find the cost of fencing the lawn at Rs. 65 per metre.
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The error in the measurement of the sides of a rectangle is 1%. The error in the measurement of its area is
Correct answer is (C) 2%
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(i) The two sides of a rectangle are x units and (10 - x) units. For what value of x, the area of rectangle will be maximum? (ii) Prove that a rectang
Correct Answer - x = 5
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The diagonals of a rhombus are 10 cm and 8 cm. If the area of rhombus is equal to `(1)/(10)th` of the area of a square, then find the cost of fencing
Correct Answer - Rs. 8
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If the marginal cost function is given by MC=2(2x+9)-1/2 and the fixed cost is Rs. 4 , find the average cost for 8 units of output.
given, The marginal cost function, M.C = 2(2x + 9)-½ we know, C = ∫(M.C) dx = ∫2(2x + 9)-½ dx = 2√(2x + 9) + k , where k is constant. here given...
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A lawn is in the form of a rectangle whose sides are in the ratio 5:3 and its area is 3375 `m^(2)`.Find the cost of fencing the lawn at Rs. 20 per met
Correct Answer - `Rs,4800`
2 Answers 1 views
The sides of a rectangle are given by the equations x=-2, x = 4, y=-2 andy=5. Find the equation of the circle drawn on the diagonal of this rectangle
Correct Answer - ` x ^(2) + y ^(2) - 2x - 3y - 18 =0`
2 Answers 1 views
Find the area of rectangle whose length is 5.3cm and breadth is 3 cm.
Correct Answer - `17.1cm^(2)`
2 Answers 1 views
The perimeter of a triangular field is 540 m and its sides are in the ratio 25 : 17 : 12. Find the the area of the field. Also, find the cost of ploug
Correct Answer - 9000 `m^(2)` Rs. 45000
2 Answers 1 views
The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle. Hint Ratio of sides
Correct Answer - `32 sqrt(3) cm^(2)`
2 Answers 1 views
The perimeter of rectangle is 34cm and length of its diagonal is 13cm. Find the length and breadth of rectangle
let length of the rectangle be L and breadth be B so by the problem perimeter 2(IL+B)=34 => L+B =17 .......(1) => L2+B2+2LB=289 ..........(2) and the square of the diagonal = L2+B2=132 =169 .....(.3) By...
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