Correct Answer - (a) Radius 4a, cantre at `(5a,0)`
(b). `V=(Q)/(4piepsilon_(0))[(1)/(|(x-3a)|)-(2)/(|(x+3a)|)]`
(c). At `x=9a` where `V=0`, the charged particle eventually crosses the circle
`v=sqrt((Qq)/(8piepsilon_(0)ma))`
(i) Indians employed in WHO located in India are residents of India because their economic interest lies in India and they live in India.
(ii) American tourist staying in India...