There is an error of `0.2%` in measurment of the redius of a sphere. Find the percentage error in its (i) volume, (ii) surface.
Answered Feb 05, 2023
Correct Answer - `(i) 0.6% (ii) 0.4%`
Correct Answer - `(1)/(5)qwr^(2),(q)/(2m)`
Correct Answer - `1.08xx10^(6)V,1.08xx10^(6)V`
Correct Answer - 36 kV, 3kV, 6kV
Correct Answer - `2.25q`
Correct Answer - (a) `+24 cm`; (b) `- 36cm` (c) `12 cm`(d) `- 180 cm`
Correct Answer - ` 4500 pi cm^(3)`
Correct Answer - `(-4)/(675 pi) cm//sec`
Correct Answer - `(i) 40 pi cm^(3) (ii) 8 pi cm^(2)`
Correct Answer - 0.003
Correct Answer - `269.5 cm^(3)`
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