Given are there numbers. If the second and the third numbers respectively are `20%` and `50%` more than the third number, then what percentage is the first of second ?
Correct Answer - B
According to the question
`2^m-2^m= 112 `
`rArr 2^n (2^(m-n)-1)= 2^4 xx 7`
Comparing exponets on both sides ,we get
`2^n-2^4 and 2^(m-n)-1= 7 `
Now ,`2^n=...