if seve times the curved surface area (A) of a cylinder is equal to 44 times the proudct of base radius (r) and height (h) then what si the formula with subject A?
Let the radius of both solids be r and their heights be h units,
According to condition,
\(\frac{r}{h}=\frac{4}{3}\\\therefore h=\frac{3r}{4}\)
TSA of cylinder = \(2\pi r(r+h)\)
TSA of cone = \(\pi r (r+l)\)
On comparing the ratios,
\(=\frac {2\pi r...