The formula with subject C is `C=(5F-160)/(9)`. Then what is the formula with subject F?
Answered Feb 05, 2023
Correct Answer - `F=(9)/(5)C+32`
We have equation of parabola, `sqrt((x-2)^(2)+(y-3)^(2))=(|5x-12y+3|)/(sqrt(5^(2)+(-12)^(2)))` Focus of the parabola is (2,3) and directrix is 5x-12y+3=0. Now, tangents drawn to parabola from point P on the directrix are perpendicular and...
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