Calculate the number of molecules of methane in 0.50 m3 of the gas at a pressure of 2.0 × 102 kPa and a temperature of exactly 300 K.


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Given :

V = 0.5 m3

P = 2.0 × 10 kPa = 2.0 × 105 Pa 

T = 300 K, 

R = 8.314 J K-1 mol-1

To find :

Number of molecules of methane gas 

Formula : 

PV = nRT

Calculation : 

According to ideal gas equation,

n = \(\frac{PV}{RT}\) 

= \(\frac{2.0\times 10^5 \times 0.5}{8.314 \times 300}\) 

= 40 mol

Number of molecules = n × NA 

= 40 × 6.022 × 1023 

= 2.4088 × 1023 ≈ 2.409 × 1025

∴ The number of molecules of methane gas present is 2.409 × 1025 molecules.

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