Correct Answer - C
`(c )` The total number of arrangments is `(11!)/(2!2!2!)=(11!)/(8)`
The number of arrangements in which `CE,H,I,S` appear in that order `"^(11)C_(5)(6!)/(2!2!2!)=(11!)/(8*5!)`
`:.` Required Proability `=((11!)/(8*5!))/((11!)/(8))=(1)/(120)`
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