A hydrogen atom moving at speed `v` collides with another hydrogen atom kept at rest .Find the minimum value of `v` for which one of the atoms may get ionized, the mass of a hydrogen atom `= 1.67 xx 10^(-27)kg`
Given: m1 = 10 kg, m2 = 4 kg
u1 = 5 m/s, u2 = 2 m/s, e = \(\frac{1}{2}\)
To find: Velocity after impact (v1 and v2)
Formulae:
i. m1u1 + m2u2 = m1v1 + m2v2
ii. e = \((\frac{v_2-v_1}{u_1-u_2})\)
Calculation:
From formula (i),
10 × 5...
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