Give the formula of a compound in which carbon exhibit an oxidation state of :
A. +4
B. +2
C. -4
Correct Answer - A n of x C = `(2.64)/(44)xx 1 = 0.06` mass of `C=0.06 xx 12 = 0.72 g` n of H = `(1.26)/(18) xx 2 = 0.14` mass...
2 Answers 1 viewsOption : b. A3(BC4)2
2 Answers 2 viewsIn combustion of methane, Carbon exhibits variation from -4 to +4. The reaction is as follows : CH4 + 2O2 → CO2 + 2H2O In CH4, The oxidation state of carbon is -4 while in...
2 Answers 1 viewsPV=nRT M.F= `(SF_(4))_(x)` `(1.02)xx22xx10^(-3)` `(0.1)/((108)x)xx0.0821xx293` `x=(0.1xx0.0821xx293)/((108)(1.02)(22.1)xx10^(-3))=1` M.F. `=SF_(4)`
2 Answers 1 views(i) H shows-0,+1 and -1 oxidation state (ii) Carbon and oxygen has variable valency (iii) Fluorine shows -1 oxidation state.
2 Answers 1 views(a) (i) Manganese (Mn) shows highest oxidalion state of +7 with oxygen but with fluorin, it shows the highest of +4 because oxygen has the ability to form multiple bonds...
2 Answers 2 viewsCorrect Answer - (a)(i)Due to small size of fluorine atom, there are strong interelectronic repulsions in the relatively small 2p-orbitals of fluorine and thus, the incoming electron does not experience...
2 Answers 1 views1. Dimensions: The dimensions of a physical quantity are the powers to which the fundamental units must be raised in order to obtain the unit of a given physical quantity. 2. Dimensional...
2 Answers 1 viewsCorrect Answer - (i) 12% (ii) 25g
2 Answers 1 viewsOption : (C) C6H6
2 Answers 1 views