Correct Answer - D
The MO configuration of `N_2` is KK, `sigma2s^2, .^*** sigma2s^2, sigma2p_x^2 , pi2p_y^2~~pi2p_z^2`
Bond order of
`N_2=1/2[N_b-N_a]=1/2[8-2]=6/2=3`
Electrons present in the outermost shell of the atom of an element are called valence electrons.
3Li is an s-block element and its electronic configuration is 1s22s1. Since it has one...
The element having valence shell electronic configuration 3s2 3p1 must be placed in the p - block of the periodic table as its last electron enters in p-subshell (3p).