A number `N_(0)` of atoms of a radio active element are placed inside a closed volume. The radioactive decay constant for the nucleus of this element

Monjur Alahi

A number `N_(0)` of atoms of a radio active element are placed inside a closed volume. The radioactive decay constant for the nucleus of this element is `lambda_(1)`. The daughter nucleus that form as a result of the decay process are assumed to be radioactive too with a radioactive decay constant `lambda_(2)`. Determine the time variation of the number of such nucleus. Consider two limiting cases `lambda_(1) gt gt lambda_(2)` and `lambda_(1) lt lt lambda_(2)`.


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Correct Answer - `[N_(0)e^(-lambda_(2)t).(lambda_(1)N_(0))/(lambda_(2))(t-e^(-lambda_(2)t))]`

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