Three capacitor of capacity 1,2 and `3muF` are connecte3d such that second and third are in series and the first one in parallel. Calculate the resultant capacity.
From second equation of motion i.e. `h=(1)/(2)"gt"^(2)(h=ut+(1)/(2)"gt"^(2)` and u=0)
`h_(1):h_(2):h_(3)......=(1)/(2)g(1)^(2):(1)/(2)g(2)^(2):(1)/(2)g(3)^(2)=1^(2):2^(2):3^(2)......=1:4:9....`
Now from the of distance travelled in `n^(th)` second `S_(n)=u+(1)/(2)a(2n01)` here u=0, a=g
`S_(n)=(1)/(2)g(2n-1)` or `S_(1):S_(2):S_(3):......=(1)/(2)g(2xx1-1):(1)/(2)g(2xx2-1):(1)/(2)g(2xx3-1)=1:3:5.....`