The critical angle for a certain wavelength of light is glass is `40^(@)`. Calculate the polarising angle and the angle of refraction in glass corresponding to it.
Correct Answer - 1.45
The path difference is `2mu t`.
Now for destructive interface it can be
`2mut=(lambda)/(2)` or `(3lambda)/(2)` or `(5lambda)/(2)` and so on………
`mu=(lambda)/(4 t),(3lambda)/(4 t),(5lambda)/(4 t)……..`
`=(580xx10^(-9))/(4xx0.3xx10^(-6)) ,...