A parallel -plate capacitor with the plate area `100cm^2` and the separation between the plate `1.0cm` is connected across a battery of emf 24 volts .Find the force of attraction between the plates.
From figure
Net charge flow through
battery = `=Q_("final")-Q_("initial")=epsilon C-(-epsilon C)=2 epsilon C`
`:. ` work done by battery (W) `=QxxV=2 epsilon C xx epsilon =2 epsilon^(2)C`
or Heat produced...
Correct Answer - decrease in energy is `(1)/(2)(epsilon_(0)AV^(2))/(d)((epsilon_(r)-1)/(epsilon_(r)));` energy is transferred to the agent introducing the slab