The photoelectric threshold wavelength for tungsten is `2400 Å`. Determine the energy of the electrons ejected from its surface when exposed to ultraviolet radiations of wavelength `1200 Å`.
Correct Answer - No
Work function `W=hv_(0)=6.626xx10^(-34)xx5.3xx10^(14)=3.5xx10^(-19)J`
As `W gt` Energy of photon, photoelectric effect will not be exhibited.
Correct Answer - 3
The threshold frequency `(v_(0))` corresponding to the wavelength `6500 Å` is `c//lambda_(0)`
Therefore, the threshold energy `=hv_(0)hc//lambda_(0)`
Substituting for `h, c` and `lambda_(0)` we gwt threshold energy...