A cheap voltmeter with an internal resistance of `30Omega` is connected to the terminals of a battery whose internal resistance is `5Omega` and true emf 1.5 V. What would be the terminal voltage as read by the voltmeter?
Answered Feb 05, 2023
Correct Answer - `1.29 V`
Correct Answer - `5/8`A
Correct Answer - `n:1,((E)/(n+1))=2V`
Correct Answer - 0.555s
Correct Answer - 80J, 66.7j, the rest is lost as heat in internal of the battery.
Correct Answer - `5.5Omega, if R gt 5.5 Omega "the battery will be changed and if" R lt 5.5Omega` the battery will be discharged.
Correct Answer - `(a) 2.40 A//s (b) 0.80 A//s (c )0.413 A (d) 0.750 A`
Correct Answer - 0.6A
Correct Answer - `29 Omega`
Correct Answer - `1.5 V, 1 Omega`
Correct Answer - `1.2 A, 0.2 A, 0.4 A, 0.6 A, 18.8 V, 10.4 V`
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