`5` different objects are to be distributed among `3` persons such that no two persons get the same number of objects. Number of ways this can be done is,
A. `60`
B. `90`
C. `120`
D. `150`
Correct Answer - B
`(b)` Division of objects can be `(0,1,4)` or `(0,2,3)`
So total number of distribution ways
`=(5!)/(0!*1!*4!)xx3!+(5!)/(0!*2!*3!)xx3!`
`=30+60=90` ways
Correct Answer - 3
Let each of the two friends have n daughters. Then probability that all the tickets go to the daughters of A is
`(.^(n)C_(3))/(.^(2n)C_(3)) = (n - 2)/(4(2n...
Correct Answer - A
The number of ways in which 20 people can be divided into two equal group is
`n(S) = (20!)/(10! 10! 2!)`
The number of ways in which...
Correct Answer - B
Total number of ways of distribution is `4^(5)`.
`therefore n(S) = 4^(5)`
Total number of ways of distribution so that each child gets at least one game...
Suppose than p and q, respectively, denote the probabilities that a thing goes to a man and a women.
`p=(a)/(a+b)and q=(b)/(a+b)`
Now, the probabilities of 0,1,2,3,… thing going to men...
Correct Answer - D
`(d)` We can take `0` indentical and `n` distinct , `1` identical and `n-1` distinct , `2` identical and `n-2` distinct and so on…
`:.` Total no....
Correct Answer - C
`(c )` Case I : When no box remains empty
Then number of ways of distribution is `.^(10-1)C_(5-1)=^(9)C_(4)=126`
Case ii : Exactly one box is empty
Number...