The variable `x`
satisfying the equation `|sinxcosx|+sqrt(2+tan^2+cot^2x)=sqrt(3)`
belongs to the interval
`[0,pi/3]`
(b) `(pi/3,pi/3)`
(c) `[(3pi)/4,pi]`
(d) none-existent
A. `[0,pi/3]`
B. `(pi/3pi/2)`
C. `[(3pi)/4,pi)`
D. None of these
Correct Answer - D
`abs(sinxcosx)+abs(tanx+cotx)=sqrt3`
`or abs(sinxcosx)+1/abs(sinxcosx)=sqrt3`
But `abs(sinxcosx)+1/(abs(sinxcosx))ge2`
hence, no solution.
Let
`S = tan^(-1) sqrt((a(a + b + c))/(bc)) tan^(-1) sqrt((b(a + b + c))/(ca)) + tan^(-1) sqrt((c (a + b + c))/(ab))`
Now, `sqrt((a(a + b + c))/(bc)) sqrt((b...
Correct Answer - A::B::C::D
Since `|tan^(-1)x| = {(tan^(-1) x," if " x ge 0),(-tan^(-1) x," if " x lt 0):}`
`rArr |tan^(-1)x| = tan^(-1) |x| AA x in R`
`rArr tan...
Correct Answer - B::D
Given `(s(s-b))/(Delta) + ((s-c))/(Delta) = (2s(s-a))/(Delta)`
`rArr s-b + s - c = 2 (s-a)`
`rArr b+c = 2a`
So, locus of vertex A is an ellipse