Correct Answer - A
`(2sin^2 91^@-1)(2sin^2 92^@-1)...(2sin^2 180^@-1)`,
In this product there exists a factor `(2sin^2 135^@-1)`, which is equal to zero
Thus, the product of all terms is zero.
`sqrt(x^2-4)`
Least value of square root is 0 when `x^2=4 of x= pm 2 " Also " x^2-4 ge 0 `
Hence `sqrt(x^2-4)in [ 0 oo).`
(ii) `sqrt(9-x^2)`
Least value...
Correct Answer - A::C
Given equation is `x^(2) + 2x sin(cos^(-1) y) + 1 =0`
Since x is real, `D ge 0`. Therefore,
`4(sin(cos^(-1)y))^(2) -4 ge 0`
or `(sin(cos^(-1)y))^(2) ge 1`...
Correct Answer - C
`(c )` Given equation is `Z^(6)+Z^(3)+1=0`
Let `Z^(3)=t`
Hence, equation becomes
`t^(2)+t+1=0`
`implies t=omega` or `omega^(2)`
`:. Z^(3)=cos"(2pi)/(3)+isin"(2pi)/(3)=e^((2npi+(2pi)/(3))i)`
`:. Z=e^(((2npi+(2pi)/(3)))/(3)i)`
Putting `n=1`, we get `theta=(8pi)/(9)(=160^(@)) in (90^(@),180^(@))`
Correct Answer - A
`(a)` Applying `C_(2)toC_(2)-C_(1)` and then `C_(3)toC_(3)-C_(2)`
`Delta=|{:(1,sinP,sin^(2)P),(1,sinQ,sin^(2)Q),(1,sinR,sin^(2)Q):}|=(sinP-sinQ)(sinQ-sinP)`
`(sinR-sinP)`
`impliesDelta=0`
Correct Answer - B
`(b)` `[{:(1,1),(0,1):}][{:(1,3),(0,1):}]=[{:(1,4),(0,1):}]`
`[{:(1,4),(0,1):}][{:(1,5),(0,1):}]=[{:(1,9),(0,1):}]`
`[{:(1,9),(0,1):}][{:(1,7),(0,1):}]=[{:(1,16),(0,1):}]`
If `n` is no. of matrices that are multiplied, then product is `[{:(1,n^(2)),(0,1):}]`
`:.r=2500`
The magnitude of the focal length are the same. But the focal length of concave is positive and the concave focal length is negative. The positive and negative sign are...