The atmosphere of earth extends upto height H and its refractive index varies with depth y from the top as `mu = 1 + (y)/(H)` . Calculate the apparent thickness of the atmosphere as seen by an observer in space.
`(1)/(f)=((mu_(i))/(mu_(s))-1) [(1)/(R_(1))-(1)/(R_(2))]`
For concave lens `[(1)/(R_(1))-(1)/(R_(2))]=-ve`
here `=1.25`
`s=1.32`
Then `((mu_(i))/(mu_(s))-1)=-ve`
Then `(1)/(f)rarr(-ve)(-ve)`
Thus it will behave like converging lens.