`CH_(3)-CH_(2)-Br` because it is a primary alkyl halide and offers less steric hindrance to the attacking nucleophile as compared to the other alkyl halide which is of tertiary nature.
Correct Answer - B
`CH_(3)-underset(D)underset(|)((C)H-underset(CH_(3))underset(|)overset(**)(C)-CH_(3)` (tertiary free radical) is maximum. Stable due to hyperconfiguration.