A thin beam of n identical positively charged particle are constrained to move in a circular orbit of radius R in a particle accelerator. Each particle has charge q and mass m and the current in the circular orbit is `I_(0)`. The magnetic flux through the circular path is made to increases at a constant rate of `beta Wb s^(–1)`. Calculate the current after the particles complete one turn.


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Correct Answer - `I = sqrt(I_(0)^(2)+(n^(2)q^(3)beta)/(2pi^(2)R^(2)m))`

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