The coefficient of `x^(28)`
in the expansion of `(1+x^3-x^6)^(30)`
is
`1`
b. `0`
c. `^30 C_6`
d. `^30 C_3`
A. 1
B. 0
C. `.^(30)C_(6)`
D. `.^(30)C_(3)`
Correct Answer - B
`(1+x^(3)-x^(6))^(30)`
`= {1+x^(3)(1-x^(3))}^(30)`
`=.^(30)C_(0) + .^(30)C_(1)x^(3)(1-x^(3))+.^(30)C_(2)x^(6)(1-x^(3))^(2) + "…."`
Obviously, each term will contain `x^(3m), m in N`. But 28 is not divisible by 3. Therefore ther will be no term containing `x^(28)`.
Correct Answer - `f(x) = x^(3) - x^(2)`
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