Consider the following balanced chemical equation:
`2A+4B_(2)+6C_(3)rarrP+2Q`
If initially 6.023xx `10^(24)` atoms orf A, 448L of `B_(2)` gas at NTP and 960 gm of `C_(3)` gas are taken, which of the following is incorrect?
[Given : Atomic mass of C=8]
A. total number of species in final mixture is 4
B. total number of species in final mixture is 3
C. A and `B_(2)` both are present in limited amount amount.
D. `C_(3)` is in excess.


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`n_(A)=10`
`n_(B)=20`
`n_(C)=(960)/(24)=40`
`2A+4B_(2)+6C_(3)rarrP+2Q`
Limiting reagent `rarrA & B_(2)`
so only 3 species will be left in final mixture.

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