`A^(2)=AxxA[(-5,-8,0),(3,5,0),(1,2,-1)]xx[(-5,-8,0),(3,5,0),(1,2,-1)]`
`=[(25-24+0,40-40+0,0+0+0),(-15+15+0,-24+25+0,0+0+0),(-5+6-1,-8+10-2,0+0+1)]`
`=[(1,0,0),(0,1,0),(0,0,1)]`
Hence, the given matrix a is involutory.
Let `P=(AB^(T)-BA^(T))`
`:. P^(T)=(AB^(T)-BA^(T))^(T)=(AB^(T))^(T)-(BA^(T))^(T)`
`=(B^(T))^(T) (A)^(T)-(A^(T))^(T)B^(T)=BA^(T)-AB^(T)`
`=-(AB^(T)-BA^(T))=-P`
Hence, `(AB^(T)-BA^(T))` is a skew-symmetric matric.
Correct Answer - C
`A^(2)=I`
or `A^(2)-I=O`
or `(A+I) (A-I)=0`
therefore, either `|A+I|=0` or `|A-I|=0`. If `|A-I| ne 0`, then `(A+I) (A-I)=Oimplies A+I=O` which is not so.
`:. |A-I|=0` and `A-I...
Correct Answer - B
Given `A, B, A + I, A+B` are idempotent. Hence,
`A^(2)=A, B^(2)=B, (A+I)^(2)=A+I` and `(A+B)^(2)=A+B`
`implies A^(2)+B^(2)+AB+BA=A+B`
`implies A+B+AB+BA=A+B`
`implies AB+BA=O`
Correct Answer - 0.25
`[(a,b),(c,1-a)]` is an idempotent matrix.
`implies [(a,b),(c,1-a)]^(2)=[(a,b),(c,1-a)]`
or `[(a,b),(c,1-a)][(a,b),(c,1-a)]=[(a,b),(c,1-a)]`
or `[(a^(2)+bc,ab+b-ab),(ac+c-ac,bc+(1-a)^(2))]=[(a,b),(c,1-a)]`
or `[(a^(2)+bc,b),(c,bc+(1-a)^(2))]=[(a,b),(c,1-a)]`
or `a^(2)+bc=a`
`a-a^(2)=bc=1//4` (given)
`f(a)=1//4`