For which of the following salt pH of its aqueous solution is independent of concentration of salt.
A. `Na_(2)HPO_(3)`
B. `NaH_(2)PO_(2)`
C. `CH_(3)COONH_(4)`
D. `CH_(3)COONa`
Correct Answer - a
`alpha=(i-1)/(n-1)or 0.8=(i-1)/(2-1)
i=1.28, DeltaT_(f)=iK_(f)m`
` =1.28xx(1.86 K kg mol^(-1))xx(0.5 mol kg^(-1))`
=1.674 K.
f.p. of solution=(273-1.674) = 271.326 K
Correct Answer - a
Since `H_(3)PO_(3)` is dibasic, 0.1 M solution =- 0.2 N solution.
`underset(("Acid"))(N_(1)V_(1))=underset(("Base"))(N_(2)V_(2))`
`(0.2 N)xx20 mL)=(0.1N)xxV_(2)`
`V_(2)=((0.2N)xx(20mL))/((0.1N))=40 mL.`
Correct Answer - d
Correct Assertion. 0.2 M awueous solution of glucose has the same lowering in freezing point temperature then 0.2 M aqueous urea solution.
Correct Reason. `K_(f)` is the...
Correct Answer - B
`Cu(M)+AgNO_(3)(N)`(queous colourless solution) `to` Resultant solution contains `Cu(NO_(3))_(2)` (blue solution) and `AgNO_(3)` (colourless solution)
Note: Here it is considered that complete `AgNO_(3)` is not utilized in the...
Correct Answer - D
Nitrite ion liberates `I_(2)` from potassium iodide turning starch blue.
`2NO_(2)^(-)+3l^(-)+4CH_(3)COOH to I_(3)^(-)+2NOuarr+4CH_(3)COO^(-)+2H_(2)O`
`I_(2)`+starch `to` blue colour
Correct Answer - A
We are given that
`P(AnnB)=P(A)P(B)`
`P(BnnC)=P(B)P(C)`
`P(CnnA)=P(C)P(A)`
`P(AnnBnnC)=P(A)(B)P(C)`
We have, `P(Avv(BnnC)=P(A)(B)P(C)=P(A)P(B)P(C)=P(A)P(BnnC)`
`impliesA and BnnC` are independent
Therefore, `S_(2)` is true. Also,
`P[(Ann(BuuC)]=P[(AnnB)uu(AnnB)nn(AnnC)]`
`=P(AnnB)+P(AnnC)-P(AnnBnnC)`
`=P(A)P(B)+P(A)P(C)-P(A)P(B)P(C)`
`P(A)[P(B)+P(C)-P(B)P(C)]`
`P(A)[P(B)+P(C)-P(BnnC)]`
`=P(A)P(BnnC)`