A particle starts from rest from the top of an inclined plane and again comes to rest on reaching the bottom most point of the inclined plane. If the coefficient of friction on some part of inclined plane is `3tantheta` and rest portion is smooth then the ratio of the rough length of the inclined to smooth length is `1 : n_(1)` then value of n is .....?


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Correct Answer - 6
`(2V^(2)sin theta cos theta)/(g)=(2V^(2)sin^(2)theta)/(2g)implies tan theta = 2 implies sin theta=(2)/(sqrt(5))and cos theta = (1)/(sqrt(5))`
`thereforeR=(2xxV^(2))/(g)xx(2)/(sqrt(5))xx(1)/(sqrt(5))=(2xx150xx2)/(10xx5)=12 " "therefore(R )/(2)=6`

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