The amount of heat released when `20 ml`,`0.5 M` `NaOH`is mixed with `100 ml`,`0.1 M` `H_(2)SO_(4)` is `xKJ`. The heat of neutralization will be `:-`
A. `-100x`
B. `-50x`
C. `+100x`
D. `+50x`
Correct Answer - A
Number of moles of `NaOH=(MV)/(1000)=(0.5xx20)/(1000)=0.01`
Number of moles of `HCl=(MV)/(1000)=(0.1xx100)/(1000)=0.01`
Heat of neutralization `=(-x)/(0.01)=-100x`
Correct Answer - D
`H^(+)+OH^(-) =13.7`
`2H^(+)+2OH^(-) rarr H_(2)O=27.4`
But energy released `=25.4`
`:. H_(1)C_(2)O_(4) rarr 2H^(+) +C_(2)O_(4)^(-2)" "DeltaH=2" kCal/mol."`
Correct Answer - B
Oxalic acid is dibasic acid hence expected heat of neutralization will be `(2xx-13.7kcal)`.
The dissociation energy of oxalic acid `2xx13.7-25.4`
`=2" kcal "mol^(-1)`