What amount of ice will remains when 52 g ice is added to 100 g of water at `40^(@)C`?
Specific heat of water is 1 cal/g and latent heat of fusion of ice is 80 cal/g.


Share with your friends
Call

Correct Answer - 2 g ice
At the stage of thermal equilibrium at `0^(@)C`
heat lost by water=Heat absorbed by ice to melt.
`msDeltaT=mL`
`100xx1xx40=mxx80`
`m=50g`
Remaining ice`=52-50=2g`

Talk Doctor Online in Bissoy App