Calculate heeat of formation of cane sugar following data: `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g),DeltaH=-68.4` kcal `C(g)+O_(2)(g)toCO_(2)(g),DeltaH=-9

Monjur Alahi

Calculate heeat of formation of cane sugar following data:
`H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g),DeltaH=-68.4` kcal
`C(g)+O_(2)(g)toCO_(2)(g),DeltaH=-94.4kcal`
`C_(12)H_(22)O_(11)(s)+12O_(2)(g)to12CO_(2)(g)+11H_(2)O(l),DeltaH=-1350.0kcal`


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Salim Ahmed Kawsar

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Correct Answer - `-535.kcal`

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For the reaction at 298 K `A(g) + B(g) iff C(g)+ D(g)` `DeltaH^(@) = -29.8 Kcal, DeltaS^(@) = - 0.1 Kcal //K` Calculate `DeltaG^(@)` and K.

Correct Answer - `DletaG^(@) = 0; k = 1` `DeltaG^(@) = - 29.8 +29.8=0` `DeltaG^(@) = - 2.303 RT log K` `K=1`

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Subtracting eq. (ii) from (i), the reqruied equation is obtained `DeltaH_("transoformation")=-94.5-(94.0)` `=94.5+94.0=-0.5kcal`

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Given that: i. `C(s) + O_(2)(g) rarr CO_(2)(g) , DeltaH =- 94.05 kcal` ii. `H_(2)(g) +(1)/(2) O_(2)(g) rarr H_(2)O(l), DeltaH =- 68.32 kcal` iii.`C_(2

Correct Answer - D Required equation is ltBrgt `2C(s)+H_(2)(g)toC_(2)H_(2)(g)` Eq. (i)+eq.(ii)-eq.(iii) gives `DeltaH=(-787)+(-286)-(-1301)` `=+228kJ`

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Calculate the `DeltaH` in joules for `C("graphite")toC("diamond")` from the following data: `C("graphite")+O_(2)(g)toCO_(2)(g):" "DeltaH^(@)=-393.5kJ`

Correct Answer - A `C("graphite")+O_(2)(g)toCO_(2)(g),DeltaH^(@)=-393.5kJ` `underline(CO_(2)(g)toC("diamond")+O_(2)(g)," "DeltaH^(@)=+395.4kJ)` On adding, `underline(C"graphite")toC("diamond"),DeltaH^(@)=+1900J=+1.9kJ)`

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Calculate the heat of formation of benzene from the following data, assuming no resonance. Bond energies : `C-C=83 kcal, C=C=140 Kcal, C-H=99 kcal` `{

We have to calculate of `Delta H` for the reaction `6 C(s)+3H_(2)(g)rarrC_(6)H_(6)(g)` For reactant: Heat of atomisation of `6` moles of `C=6xx170.9 kcal` heat of atomisation of `6` moles of...

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From the following data of heats of combustion, find the heat of formation of `CH_(3)OH(l)` `CH_(3)OH(l)+(3)/(2)O_(2)(g)toCO_(2)(g)+2H_(2)O(l),DeltaH=

`-240kJ" "mol^(-1)`.

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Given `C_(("graphite"))+O_(2)(g)toCO_(2)(g),` `Delta_(r)H^(0)=-393.5kJ" "mol^(-1)` `H_(2)(g)=+(1)/(2)O_(2)(g)toH_(2)O(1),` `Delta_(r)H^(0)=-285.8" kJ

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If `{:(H_(2)+1//2O_(2)rarrH_(2)O",",,,,DeltaH= -68 kcal),(K+H_(2)OrarrKOH(aq)+1//2H_(2)",",,,,DeltaH= -48 kcal),(KOH+"water"rarrKOH(aq)"," ,,,,DeltaH=

Correct Answer - `-102 kcal`

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Correct Answer - D `C(s)rarrC(g)" "`can be obtained as, `Delta H=DeltaH_(1)-DeltaH_(2)-(1)/(2)DeltaH_(3)+DeltaH_(4)`

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For the reaction at `298 `K `A(g) + B(g) hArr C(g) + D(g)` If `DeltaH^(@) =-29.8` Kcal and `DeltaS^(@) Kcal K^(-1)` then calculate reaction constant (

Correct Answer - 1 `DeltaG^(@) = DeltaH^(@) - TDeltaS^(@)` `" "=-29.8 - 298 xx (-0.1)` `" "=-29.8 + 29.8 =0` = nRTIn (K) `" "K=1`

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