In a reversible chemical reaction having two reactants in equilibrium, if the concentration of the reactants are doubled then the equilibrium constant will :
A. one-fourth
B. halved
C. doubled
D. the same
Correct Answer - D
Consider a hypothetical change.
`A+BhArrC+D`
For the reaction.
`K_(eq)=([C][D])/([A][B])`
For the above reaction if concentration of reactions are doubled then the rate of forward reaction increases for a short time but after sometime equilibrium wil established. So concentration has no effect on equilibrium constant. it remains unchanged after increasing the concentration of reactants.