Let `A( vec a)a n dB( vec b)`
be points on two skew lines ` vec r= vec a+lambda vec pa n d vec r= vec b+u vec q`
and the shortest distance between the skew
lines is `1, w h e r e vec pa n d vec q`
are unit vectors
forming adjacent sides of a parallelogram enclosing an area of 1/2 units. If
angle between`A B`
and the line of shortest distance is `60^0,`
then `A B=`
a. `1/2`
b. `2`
c. `1`
d. `lambda R={10}`
A. `(1)/(2)`
B. 2
C. 1
D. `lamdaepsiR-{0}`