A white substance `(A)` reacts with dilute `H_(2)SO_(4)` to produce a colourless gas `(B)` and a colourless solution `( C)`.The reaction between `(B)`

Monjur Alahi

A white substance `(A)` reacts with dilute `H_(2)SO_(4)` to produce a colourless gas `(B)` and a colourless solution `( C)`.The reaction between `(B)` and acidified `K_(2)Cr_(2)O_(7)` solution produces a green solution and a slightly coloured precipitate `(D)`.The substance `(D)` burns in air to produce a gas `(E)` which reacts with `(B)` to yield `(D)` and a colourless liquid. Anhydrous copper sulphate is turned blue on addition of this colouless liquid.Addition of aqueous `NH_(3)` or `NaOH` to `( C)` produces first a white precipitate which dissolves in the excess of the respective reagent to produce a clear solution in each case. Identify `(A),(B),( C),(D)` and `(E)`.


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Salim Ahmed Kawsar

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Correct Answer - (A)`ZnS` ; (B)`H_(2)S` ; (C )`ZnSO_(4)` ; (D)`S` ; (E)`SO_(2)`
`ZnS+H_(2)SO_(4)to ZnSO_(4) + H_(2)S`
`Cr_(2)O_(7)^(2-) + 3H_(2)S+8H^(+) to 2Cr^(3+) ("green solution")+3S darr +7H_(2)O`
`S+O_(2) to SO_(2) , 2H_(2)S +SO_(2) to 2H_(2)O+3S`
`Zn^(2+)+2OH^(-) toZn(OH)_(2) darr` (white)
`Zn^(2+)+2NH_(3)+ H_(2)O hArrZn(OH)_(2) darr("white")+NH_(4)^(+)`
`Zn(OH)_(2) darr +4NH_(3) hArr [Zn(NH_(3))_(4)]^(2+) +2OH^(-)`

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