A white crystalline substance dissolves in water.On passing `H_(2)S` in this solution, a black precipitate is obtained.The black precipitate dissolves completely in hot `HNO_(3)`.On adding a few drops of concentrated `H_(2)SO_(4)`, a white precipitate is obtained.This precipitate is that of
A. `BaSO_(4)`
B. `SrSO_(4)`
C. `PbSO_(4)`
D. `CdSO_(4)`


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Correct Answer - C
`Pb^(2+)+H_(2)StoPbSdarr("black")+2H^(+), 3PbS+8HNO_(3)to3Pb(NO_(3))_(2)+2NOuarr+3Sdarr+4H_(2)O`
`Pb^(2+)+SO_(4)^(2-) to PbSO_(4) darr` (white)

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