The rate constant of a first order reaction at `27^(@)C "is" 10^(-3)"min"^(-1)`.The constant ( in `"min"^(-1)`) at `17^(@)C` for this reaction ?
A. `10^(-3)`
B. `5xx10^(-4)`
C. `2xx10^(-3)`
D. `10^(-2)`
According to available data:
`a=2.0 xx 10^(-3) mol L^(-1), (a-x) = 5.0 xx 10^(-4) mol L^(-1), k=3.0 xx 10^(-3) min^(-1)`
`t=(2.303)/k log a/(a-x) = (2.303)/(3 xx 10^(-3) min^(-1)) = 4.62...
Correct Answer - A-r; B-s ; C-q; D-p
Zero order x=kt
First order `K=1/t"In"a/(a-x)`
Second order `K=1/t[1/(a-x)-1/a]`
Third order `K=1/(2t)[1/(a-x)^2-1/a^2]`
Correct Answer - B
Remainin concetration of reactant after 20 min
`=(1)/(4)xx102.5"mol"L^(-1)`
`"Rate"=kxx["Reactant"]=(0.693)/(t_(1//2))xx["Reactant"]`
`=(0.693)/(10xx2.5=0.0693xx2.5 "mol"L^(-1) min^(-1)`