The rate of the reaction `2NO+O_(2)rarr2NO_(2),"at" 25^(@)C` is
`r=k[NO]^(2)[O_(2)]`
If the initial concentrations of the reactant are `O_(2)=0.040 "mol"L^(-1) and NO==0.01 "mol" L^(-1)` , the rate constant of the reaction is :
A. `7.0xx10^(-2)L"mol"^(-1)s^(-1)`
B. `7.0xx10^(-4)L^(2)"mol"^(-2)s^(-1)`
C. `7.0xx10^(2)L^(2)"mol"^(-2)s^(-1)`
D. `7.0xx10^(3)L^(2)"mol"^(-2)s^(-1)`


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Correct Answer - D
`0.028=k[0.01]^(2)[0.040]`

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