An electromagnetic radiation has an energy of 13.2 keV. Then the radiation belongs to region of

Correct Answer - B Given `E = 9 xx 10^(-4) NC^(-1)` We know that, `c = (E)/(B) rArr B = (9 xx 10^(-4))/(3 xx 10^(8)) = 3 xx 10^(-12)T`

It is given that, `E_(K)=35.2keV,E_(L)=5.25keV,E_(M)=0.55 keV` `rArr" " E_(K)-E_(L)=(hc)/(lambda_(K_(A_(alpha))))=hv_(K_(alpha))` `rArr(35.2-5.25)xx10^(3)xx1.6xx10^(-19)=6.6xx10^(-34)v_(K_(alpha))` `rArr" " v_(K_(alpha))=(29.95xx10^(3)xx1.6xx10^(-19))/(6.6xx10^(-34))=7.2xx10^(-34)Hz` Similarly, `E_(K)-E_(M)=hv_(K_(beta))` `rArr" " v_(K_(beta))=((35.2-0.55)xx10^(3)xx1.63xx10^(-19))/(6.6xx10^(-34))=8.4xx10^(18)Hz` Also, `E_(L)-E_(M)=hv_(k_(alpha))` `rArr" " ((5.25-0.55)xx10^(3)xx1.6xx10^(-19))/(6.6xx10^(-34))=1.1xx10^(18)Hz`

Correct Answer - A Transverse waves are those waves in which the particles of the medium oscillate perpendicular to the direction of wave propagation.

Correct Answer - C The electromagnetic wave contains sinusoidally time varying electric and magnetic field which act perpendicualr to each other as well at right angle to the direction of propagation...

Correct Answer - B `v=(1)/(sqrt(muepsilon))=(c)/(sqrt(mu_(r)epsilon_(r))`

Correct Answer - B Consider a plane perpendicular to the direction of propagation of the electromagnetic wave. If electric charges are present in this plane, they will be set and sustained...

Correct Answer - A Electromagnetic waves have linear momentum as well as energy. This concludes that they can exert radiation pressure by falling beam of electromagnetic radiation on an object.

Correct Answer - A Electromagnetic waves can carry energy from one place to another. This makes radio and TV signal broadcasting possible. Also light carries energy from the sun to the...

Correct Answer - A The basic difference between various types of electromagnetic waves lies in their wavelengths or frequencies since all of them travel through vacuum with the same speed. Consequently,...

Correct Answer - A `("Energy loss")/("Initial KE") = (4m_(1)m_(2))/((m_(1) + m_(2))^(2)) = (4(1)(2))/((1+2)^(2)) = 8/9` After `1^(st)` collision `DeltaE_(1) = 8/9 E_(0)` After `2^(nd)` collision `DeltaE_(2) = (8)/(9)E_(1)`, After `n^(th)` collision...