Hailstone at `0^@C` from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt? (`g=10 m//s`)
A. `(1)/(33)`
B. `(1)/(8)`
C. `(1)/(33) xx 10^(-4)`
D. All of it will melt
Correct Answer - A
M= mass of hailstone falling
m = mass of hailstone melting
As Mgh = ml.
S0 `(m)/(M) = (gh)/(L) = (10 xx 10^(3))/(33 xx 10^(3)) = (1)/(33)`
`PCl_(3), SOCl_(2) and PCl_(5), SOCl_(2)` is the best reagent because the products of the reaction besides acyl chloride are `SO_(2)` and HCl which are gases and easily separated