The `pK_(a_1), pK_(a_2) and pK_(a_3)` value for the amino acid cysteine `(HS-CH_2-undersetunderset(NH_2)(|)CH-COOH)` are respectively 1.8, 8.3, 10.8. What is isoelectric point of cysteine amino acid ?
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pH of a mixture which is 0. 1 M in `CH_(3)COOH` and 0.05 M in `(CH_(3)COOH)_(2)Ba` is `[pK_(a)` of `CH_(3)COOH=4.74]`
Correct Answer - A `[CH_(3)COO^(-)]=2[(CH_(3)COO)_(2)Ba]` `=2 xx 0.05 =0.1 M` `[CH_(3)COOH]=0.1M` `pH=pK_(a)+log.(["Salt"])/(["Acid"])` `=4.74 +log.(0.1)/(0.1)=4.74`
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`Ph-undersetunderset(OH)(|)oversetoverset(Me)(|)C-undersetunderset(OH)(|)oversetoverset(Me)(|)C-Et overset(conc.H_2SO_4,Delta)to`Products How many num
Correct Answer - 4 `Ph-undersetunderset(OH)(|)oversetoverset(Me)(|)C-undersetunderset(OH)(|)oversetoverset(Me)(|)C-Et`
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`CH_3-undersetunderset(O)(||)C-OHoverset(14)overset(NaHCO_3)to(P gas)underset((1)H_3O^(o+))overset((1)PhCH_2MgBr)to(Q)` `CH_3-undersetunderset(O)(||)o
Correct Answer - C `CH_3-oversetoverset(O)(||)C-OH oversetoverset(14)((NaHCO_3))to CH_3COoverset(-)Ooverset(+)Na+H_2O+overset(14)(CO_2)` `overset(14)CO_2underset((2)H_3O^(o+))overset((1)PhCH_2MgBr)toPhCH_2overset(14)COOH` `CH_3-undersetunderset(O)(||)oversetoverset(O)(||)S-OHoverset(14)overset(NaHCO_3)toCH_3SO_3Na+H_2O+overset(14)CO_2` `overset(14)CO_2underset((2)H_3O^(o+))overset(14)overset((1)PhCH_2MgBr)to Ph overset(14)CH_2 overset(14)COOH`
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Number of optically inactive stereoisomers of the following molecule is . `CH_3-CH=CH-undersetunderset(OH)(|)CH-CH=CH-undersetunderset(OH)(|)CH-CH=CH-
Correct Answer - 4 No of optically inactive isomers `=2 (n-1)/2 =2 (5-1)/2=2 4/5 =2^2 =4`
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Write the correct `IUPAC` name of the following: (i) `H_(3)C-undersetunderset(Cl)(|)(CH)-undersetunderset(Br)(|)(CH)-undersetunderset(CH_(2)CH_(3))(|)
(i)`4`-Bromo-`5`-chloro-`3`-methylhexane-`3`-sulphonic acid , (ii)`4`-Sulphopentanoic acid
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If `0<a_1<a_2<ddot<a_n ,` then prove that `tan^(-1)((a_1x-y)/(x+a_1y))+tan^(-1)((a_2-a_1)/(1+a_2a+1))+tan^(-1)((a_3-a_2)/(1+a_3a_2))++tan^(-1)((a_n-a_
Here, `tan^(_1) ((a_(1) x- y)/(a + a_(1) y)) = tan^(-1) ((a_(1) - (y)/(x))/(1 + a_(1) (y)/(x))) = tan^(-1) a_(1) - tan^(-1) (y)/(x)` `tan^(-1) ((a_(2) -a_(1))/(1 + a_(2) a_(1))) = tan^(-1)...
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Let `A_1,A_2,A_3,...,A_n` are n Points in a plane whose coordinates are `(x_1,y_1),(x_2,y_2),....,(x_n,y_n)` respectively. `A_1A_2` is bisected at the
`P_1` is midpoint of `A_1A_2`. `therefore" "P_1-=((x_1+x_2)/(2),(y_1+y_2)/(2))` `P_2` divides `P_1A_3` in `1:2`. `therefore" "P_2-=((2((x_1+x_2)/2)+x_3)/(2+1),(2((y_1+y_2)/2)+y_3)/(2+1))` `-=((x_1+x_2+x_3)/(3),(y_1+y_2+y_3)/(3))` Now, `P_3` divides `P_2A_4` in ` 1:3` `therefore" "P_3-=((3.((x_1+x_2+x_3)/3)+x_4)/(3+1),(3.((y_1+y_2+y_3)/3)+y_4)/(3+1))` `-=((x_1+x_2+x_3+x_4)/(4),(y_1+y_2+y_3+y_4)/(4))` Proceeding in this manner, we...
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If the equation of the locus of a point equidistant from the points `(a_1,b_1)` and `(a_2,b_2)` is `(a_1-a_2)x+(b_2+b_2)y+c=0`, then the value of C is
Correct Answer - D Let (h,k) be the point on the locus. Then by the given conditions, `(h-a_1)^1+(k-b_1)^2=(h-a_2)^2+(k-b_2)^2` or `2h(a_1-a_2)+2k(b_1-b_2)+a_2^2+b_2^2-a_1^2=0` `h(a_1-a_2 )+k(b_1-b_2)+(1)/(2)(a_2^2+b_2^2-a_1^2-b_1^2)=0` .....(1) Also, since (h,k) lies on the given locus,...
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If `(1+x)^5=a_0+a_1x+a2x2+a_3x^3=a_4x^4+a_5x^5,` then the value of `(a_0-a_2+a_4)^2+(a_1-a_3+a_5)^2` is equal to `243` b. `32` c. `1` d. `2^(10)`
Correct Answer - B Put `x = i` `(1+i)^(5) = (a_(0) - a_(2) + a_(4)) + i(a_(1)-a_(3)+a_(5))` `rArr |1+i|^(5) = |(a_(0) - a_(2) + a_(4)) + i(a_(1) - a_(3) + a_(5))|`...
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If `p` is the probability that a man aged `x` will die in a year, then the probability that out of `n` men `A_1,A_2, A_n` each aged `x ,A_1` will die
Correct Answer - C Let the probability that a man aged x dies in a year p. Thus the probability that a man aged x does not die in a year...
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