`H_3PO_3+HNO_3+(NH_4)_2MoO_4to` Oxidation number of Mo in product is x.
`Cr_2O_7^(2-)+H^(+)+NaCl to` Oxidation state of Cr in product is y.
`SCN^(-)+MnO_2to`Number of `pi` bonds in sulphur containing product is z.
Find x+y+z


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Correct Answer - 16
x=+6`(NH_4)_3 PMo_12 O_40`
y=+6 `CrO_2Cl_2`
z=4
`ZtoN^(@)C-S-S-C^(@)N`

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