Assertion: Terminal voltage of a cell is greater than emf of cell during charging of the cell.
Reason: The emf of a cell is always greater than its terminal voltate.
Correct Answer - C
During charging, `E=V+ir` (due to reversed current). In case of charging emf of a cell is less than its terminal voltage while in case of discharging emf Is is greater than terminal voltage.
Correct Answer - C
(c ) Correct reason : The effect of concentration on electrode potentialis guided by Nernst equation. On doubling the concentration, emf will remain unchanged since `([Zn^(2+)])/([Cu^(2+)])` will...
Correct Answer - C
(c ) `DeltaG=DeltaG^(@)+RT" In "Q`
It `E_(cell)` is +ve,`DeltaG` is -ve
(Cell working is feasible)
Similarly `E_(cell)` is -ve, `DeltaG^(@)` is -ve.
`:. RT " In "`Q...
Correct Answer - B
The time period in sum position, `T_(s)=2pi sqrt((I_(s))/(M_(s)H))`
`where, " "I_(s)+I_(1)+I_(2) and M_(s)=M_(1)+M_(2)`
` " " T_(s)=2pi sqrt((I_(1)+I_(2))/((M_(1)+M_(2))H))`
Time period in difference position,
` " " T_(d)=2pi...
Correct Answer - D
IF a conducting rod of length l moving with a uniform velocity v perpendicular to a uniform magnetic field B, then induced emf will be e =...
Correct Answer - B
The average value of alternating emf `E=E_(0)sinomega` t over a positive half cycle is
`E_(av) half cycle =(2E_(0))/(pi)=0.6369`
Percentage of `E_(av)=0.6369xx100=63.69%`
Also rms value of emf is...
