A radioactive substance emit 100 beta particfles in the first 2 s and 50 beta particles in the next 2s. The mean life of the sample is
A. 4 s
B. 2 s
C. `(2)/(0.693)s`
D. `2xx0.693 s`
Correct Answer - C
Given in 1st two seconds `100beta` particles and in next two seconds `50beta` particles are emitted.
`:.T_(1//2)=2s`
Hence, mean life, `T=(t_(1//2))/(0.693)=(2)/(0.693)`
Correct Answer - B
`8 alpha` have been emitted
`4 beta^(-)` have been emitted
`2 beta^(+)` have emitted
`alpha` reduces atomic number by 2
`beta^(-)` increases atomic number by 1
`beta^(+)`...
Correct Answer - A
No. of nuclei remains at any instant
`N= N_(0)/(2^(t//T_(1//2)))=N_(0)/sqrt(2)`
`N_("decayed")=N_(0)-N=N_(0) [1-1/sqrt(2)]`
`=1/24xx6.023xx10^(23)xx0.3`
`~~7.5xx10^(21)`